Question

if an angle is 30 degree more than one half of it's compliment. find the measure of the angle

Answer 1

Let the angles be x , (x+60)/2 Then the sum of these  is 903x+60 = 180 3x = 120x = 40 (x+60)/2 = 50
The angles are 40,50

Answer 2

1st angle = 38°

2nd angle = 52°

__________________________

$\orange{\bigstar}$★ Given {\green{\bigstar}★[/tex]

1 . The measure of one angle is 12 degree more than half the measure of its compliment

$\orange{\bigstar}$★ To Find \green{\bigstar}★[/tex]

Two angles

$\orange{\bigstar}$★ Solution $\green{\bigstar}★$

Let 1st angle be , " x "

So , Complementary angle be ,

" ( 90 - x ) "

From condition 1 ,

⇒ x = ( 90 - x ) / 2 + 12

⇒ 2x = 90- x + 24

⇒ 2x + x = 90 + 24

⇒ 3x = 114

⇒ x = 38$\pink{\bigstar}★$

So ,

1st angle , x = 38° $\pink{\bigstar}★$

2nd angle , ( 90 - x ) = 52°$\pink{\bigstar}★$

__________________________