If an angle is four times its supplement, how much each of them measure
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supplement and complement of an angles are (180-0)^0 and (90-0)^0.
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Let angle Be X. And Its Supplement be Y.
Now Givem. X=4Y (1)
But X+Y=180°
=4Y+Y=180° ( from(1) )
=5Y=180°
→Y=180/5
→Y=36°
so X=4(36°)=144°( from (1) )
Now Givem. X=4Y (1)
But X+Y=180°
=4Y+Y=180° ( from(1) )
=5Y=180°
→Y=180/5
→Y=36°
so X=4(36°)=144°( from (1) )
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