If an angle of a parallelogram is four-fifths of it's adjacent angle, find the angles of the parallelogram.
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HIIIII HERE IS YOUR ANSWER....,
In parallelogram ABCD,
angleB + angleC=180......(adjacent angles)
4/5angleC+angleC=180
9/5 angleC=180
angle C =180×5/9
angleC = 100
angleB+angleC=180
angleB=80
angleB=angleD=80. ........ (opposite angles)
angleC=angleA=100. ......(opposite angles)
HOPE IT HELPS YOU.
In parallelogram ABCD,
angleB + angleC=180......(adjacent angles)
4/5angleC+angleC=180
9/5 angleC=180
angle C =180×5/9
angleC = 100
angleB+angleC=180
angleB=80
angleB=angleD=80. ........ (opposite angles)
angleC=angleA=100. ......(opposite angles)
HOPE IT HELPS YOU.
ria113:
is it right
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