If an angle of a parallelogram is two third of its adjacent angle then find smallest angle of the parallelogram
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Answered by
297
let adjacent angles be x
then, other angle = 2/3x
.
we know that opposite angles of parallelogram are equal
.
and sum of all 4 sides of parallelogram is 360
.
= x+x+2x/3+2x/3 = 360
= 2x+4x/3 = 360
= 6x+4x/3 = 360. (by making denominator same)
= 10x/3 = 360
= 10x = 360/3
= x = 108
.
then, other angle = 2/3×108= 2× 36
= 72
.
the smallest angle is = 72 degree
.
hope it helped☺️
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55
answer is in the attachment
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