if an angle of a parallelogram is two third of its adjacent angle find the angles of parallelogram
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Kon sa 5........
5/3x = 180 5th line
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165
Let one angle=x
Let second angle=2/3of x =2/3x
1st angle+2nd angle=180°
x+2/3x=180°
5/3x=180°
x=180°×3/5
x=36×3
x=108°
so one angle=x=108°
second angle=2/3x=2/3×108°=72°
Let second angle=2/3of x =2/3x
1st angle+2nd angle=180°
x+2/3x=180°
5/3x=180°
x=180°×3/5
x=36×3
x=108°
so one angle=x=108°
second angle=2/3x=2/3×108°=72°
but esmsi 5 kaha se aya
Isme 5 kahan se aaya
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