if an AP a=1 an=20 sn=390 then n is
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a=1
An=nth term=20
1+(n-1)d=20
d=19/(n-1)
Sum of nth term=390
n/2[2×1+(n-1)d]=390
n[2+(n-1)(19/n-1)]=390×2
n[2+19]=780
n=780/21=260/21
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