If an ap the sum of first ten terms is 4 times the sum of first five terms then the ratio of first term and common difference is
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10/2(2a+(10-1)d)=4(5/2(2a+(5-1)d))
5(2a+9d)=10(2a+4d)
2a+9d=2(2a+9d)
2a+9d=4a+18d
-2a=9d
a/d=-9/2
5(2a+9d)=10(2a+4d)
2a+9d=2(2a+9d)
2a+9d=4a+18d
-2a=9d
a/d=-9/2
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