Question

if an arc of a circle having radius r subtends an angle of measure 90 at centre then area of minor segment is

Answer 1

Step-by-step explanation:

Area of minor segment =πr^2 - πr^2A/360

= πr^2 (1 -A/360)

=22/7(1 - 90/360)

=22/7 *r^2(3/4)

area of segment=22/7*r^2(3/4)