If aN = {ax : x belongs to N} , then the set 6N intersection 8N is equal to
Answers
Answer:
All multiple of 24
Step-by-step explanation:
L. C. M of 6 & 8 = 24
Concept: The definition of a set, which is always the same from person to person, is a grouping of clearly defined items or elements. A capital letter designates a set. The cardinal number of a set is the number of elements in the finite set.
If set A and set B are two sets, then set A intersection with set B is the set that only contains the elements that are shared by set A and set B. It is shown as A B.
As an illustration, if A = {1, 2, 3}, and B = {4,5, 6}, then A intersecting B is:
A ∩ B = { } or Ø
The intersection of A and B will result in a null set because they don't share any elements.
Given: aN = {ax : x belongs to N}
To find: 6N ∩ 8N
Solution: As it is given aN = {ax : x belongs to N}, then
6N = {6x: x ∈ N} = {6, 12, 18, 24, 30, ……} [multiples of 6]
8N = {8x: x ∈ N} = {8, 16, 24, 32, ……} [multiples of 8]
6N ∩ 8N = {24; 48; 72.......} [multiples of 24]
{24x: x ∈ N};
=24N;
Hence, 6N ∩ 8N = 24N
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