Question

if an electric charge of +5 uc is kept in field of strength 10N/c .what force will the charge experience​

Answer 1

Answer:

50$\mu$N

Explanation:

Electric field (vector E) is given by expression:

$\\\tt \dfrac{Electrostatic \ Force}{Charge}$

Since here:

E = 10N/C and

Q(charge) =5$\\\tt \mu$ C

Using the above expression

$\\\tt Force = E \times Q \\= 10\dfrac{N}{C} \times 5\mu C\\=50\mu N$

Answer 2

Answer:

50 columb

Explanation:

F=q×e

q=electic charge

e= electric field of strength

Given q= +5uc

e= 10N/c

F= 5×10

= 50columbs