Question

If an electric iron of 1200 W is used for 30 m every day find the electric energy consumed in the month of aprill. ​

Answer 1

Answer:

18kW h

Explanation:

Given,

Power = 1200W = 1.2kWh

Time = 30 min / day × 30 days

= 0.5h×30

= 15 h

Energy = Power × Time

= 1.2 × 15 = 18kW h.

Answer 2

$\huge\underline\mathfrak\color {aqua}Answer:$

Given that,

Power =1200W

$\leadsto$1.2kWh

Time = $\frac {30 min}{day}\times30 days$

=0.5h×30

$\leadsto$ 15 h

Energy =Power×Time

=1.2×15

$\leadsto$ 18kWh.