If an electron is accelerated by 100 volt then calculate the de broglie wave length of electron
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The answer is 1.227
hope this helps you quickly
hope this helps you quickly
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kinetic energy of an electron == Charge of Electron x Potential Difference
= 1.6 x 10^(-19) C x 100 V
= 1.6 x 10^(-17) J
mass of an electron =9.1 x 10^(-31) kg.
momentum =mass x velocity
=5.39 x 10^(-24) kg m s^(-1)
so, putting this values in DE brogile wavelength formula .we get
de brogile Wavelength = Planck's Constant/Momentum
= 6.626 x 10^(-34) / 5.39 x 10^(-24) m
= 1.2293 x 10^(-10) m
= 1.2293 Å
hope it helped you
= 1.6 x 10^(-19) C x 100 V
= 1.6 x 10^(-17) J
mass of an electron =9.1 x 10^(-31) kg.
momentum =mass x velocity
=5.39 x 10^(-24) kg m s^(-1)
so, putting this values in DE brogile wavelength formula .we get
de brogile Wavelength = Planck's Constant/Momentum
= 6.626 x 10^(-34) / 5.39 x 10^(-24) m
= 1.2293 x 10^(-10) m
= 1.2293 Å
hope it helped you
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