If an electron is accelerated by a potential difference of 1volt calculated the gain in energy in joul and electron volt
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Gain in energy=q xV
where q is charge of particle and V is its potential difference.
q for electron=-1.6 x 10^-19
gain=1.6x 10^-19 x 1 eV
=1.6x 10^-19eV
Now we know that
1eV=1.6 x10^-19J
so gain in joule=(1.6 x10^-19)x(1.6 x10^-19)J
=2.56 x10^-38J ans
where q is charge of particle and V is its potential difference.
q for electron=-1.6 x 10^-19
gain=1.6x 10^-19 x 1 eV
=1.6x 10^-19eV
Now we know that
1eV=1.6 x10^-19J
so gain in joule=(1.6 x10^-19)x(1.6 x10^-19)J
=2.56 x10^-38J ans
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