if an element m has 2 isotopes m40,m42 the average atom is 41.2 calculate percentage of abundance of both the isotopes
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Answer:
80, 20
Explanation:
%age abundance of m40 be x
then %age abundance of m42 be (100-x)
the avg at mass= (x×40)+(100-x)42
-----------------------
100
so, 40x + (100-x)42 = 41.2
--------------------
100
40x + 4200 - 42x = 41.2 × 100
-x = 4120 - 4200
x = 80
so,
100-x = 100 -80 = 20
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