If an integer is added to its square the sum is 90. find the integer
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Answered by
6
Let the required no. be x.
therefore, + x = 90
or, + x - 90 = 0
or, (x - 9)(x +10) = 0
Therefore, x = 9 or -10
therefore, + x = 90
or, + x - 90 = 0
or, (x - 9)(x +10) = 0
Therefore, x = 9 or -10
Answered by
2
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Suppose the integer be x.
According to the question we have;
x2+x = 90⇒x2+x−90 = 0⇒x2+10x−9x−90 = 0⇒x(x+10)−9(x+10) = 0⇒(x−9)(x+10) = 0⇒x = 9 and x = −10
Taking the positive integer we have the required integer as 9.
Suppose the integer be x.
According to the question we have;
x2+x = 90⇒x2+x−90 = 0⇒x2+10x−9x−90 = 0⇒x(x+10)−9(x+10) = 0⇒(x−9)(x+10) = 0⇒x = 9 and x = −10
Taking the positive integer we have the required integer as 9.
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