if an iron wire is drawn to decrease its radius by 0.5%.Then percentage of increase in its resistance will be
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Delta R/R×100=-4Delta r/r×100
DeltaR/R%=-4×0.5=2%
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Answered by
18
Answer:-
∆ R/R×100
=-4∆ r/r×100
∆R/R%
=-4×0.5
=2%
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