Question

if an isosceles triangle abc where ab= ac= 6cm inscribed in a circle of radius 9cm. find the area of the triangle

Answer 1

AREA OF A TRIANGLE =
$\frac{1}{2} \times b \times h$
SO

LOOK IN THE FIG.

STEP 1.

LET AP =x

and OP= 9-x

GIVEN OA=9 (Radii)

IN TRIANGLE ABP ( SHOW IN FIG.)

=>BP²=AB²-AP² ( EQ. . . . . 1)

STEP 2 .

IN TRIANGLE DBC

BP²=OB²-OP² ( EQ. . . . . . . 2)
.
SO
FROM EQ 1 AND 2 WE GET

=>AB²-AP²=OB²-OP²

=>6²-x²=9-(9-x)²
=>x=2cm
mean AP=2CM

PUT THE VALUE OF AP IN EQ .1 WE GET

BP²=(6)²-(2)²
=>√36-4
=>√32 cm

AREA OF TRIANGLE =

$\frac{1}{2} \times b \times h$
so AP = 2 cm. which is hight of ∆ ABC

BC= 2×OB
= 2√32 cm

so.AREA

=
$\frac{1}{2} \times 2 \times 2 \sqrt{32}$
=
$2 \sqrt{32}$
=
$2 \sqrt{2 \times 2 \times 2 \times 2 \times 2}$
=
$2 \times 4 \sqrt{2}$
=8√2 cm ²

Answer 2

Answer:

Step-by-step explanation:a simple way is to calculate that is to convert days into week

61 /7 or 8 weeks(56 days) +5 days

8 weeks (friday )+5 days(sat, sun, mon, tue, wed)

=> Question is saying that after 61 days means 8 weeks (friday )+5 days(sat,sun,mon,tue,wed, ?)_____then  ? = after wednesday =Thursday