if an isosceles triangle angle at top vertex is twice the sum of base angle find all exterior angles of triangle
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we know, in isosceles traingle , two sides are same , so two angles are also same .
let ∅ , ∅ and ¢ are the angle of isosceles triangle .
so, ∅ + ∅ + ¢ = 180°
a/c to question,
¢ = 2( ∅ + ∅ ) = 4∅
put this in above equation ,
∅ + ∅ + 4∅ = 180°
6∅ = 180°
∅ = 30°
and ¢ = 120°
hence , 30° , 30° and 120° are the angle of isosceles ∆
let ∅ , ∅ and ¢ are the angle of isosceles triangle .
so, ∅ + ∅ + ¢ = 180°
a/c to question,
¢ = 2( ∅ + ∅ ) = 4∅
put this in above equation ,
∅ + ∅ + 4∅ = 180°
6∅ = 180°
∅ = 30°
and ¢ = 120°
hence , 30° , 30° and 120° are the angle of isosceles ∆
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