Question

If An=n(n-3)/n+4 ,then find 18th term of this sequence.answere it step by step with reason.

Answer 1

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Answer 2

Answer:

  18th term = $\frac{135}{11}$

Explanation:

• Given that the Nth term of the sequence, Aₙ=n(n-3)/n+4
• In mathematics mainly there are two types of progression. Arithmetic progression and geometric progression.
• Arithmetic progression is a sequence of numbers in which the difference between any two consecutive numbers will be a constant value. A geometric progression is a sequence in which each consecutive element is obtained by multiplying the preceding element by a constant value. The constant value is called as a common difference.
• Here we have to find the 18th term of given sequence, A₁₈.

• 18th term, A₁₈ = $\frac{18(18-3)}{18+4}$

                               = $\frac{18 * 15}{18+4}$

                               = $\frac{9 * 15}{11}$

                               = $\frac{135}{11}$

• Therefore, 18th term of the sequence, A₁₈ = $\frac{135}{11}$

To know more about the topic, please go through the links;

https://brainly.in/question/7152218

https://brainly.in/question/20677544

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