If an object at a distance of 6400 km from the center of the earth weighs 50N , what will be its weight if it is shifted to 12800 km from the center of the earth?
Answers
Answered by
40
here,
i am writing the answer in the variables by which we generally denote the values.
soln: Let k = GMm
now,
F = GMm/R²
50 N = K/(6400)²
K=50 N×(6400)²-------------------------------------1
NOW when distance is 12800 km,
F = GMm/R²
F = 50 N×(6400)²/(12800)²
F = 50 N/4
=12.5 N
WEIGHT OF THE OBJECT AT 12800 KM FROM THE CENTRE OF THE EARTH = 12.5 N
Answered by
0
Answer:
∆
ll
Explanation:
same as above
I am sorry if I am wrong
Similar questions