if an object completes one rotation in 6 minutes find the distance displacement average speed and average velocity in its journey of 63 Si radius circle track 210
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Explanation:
given
total time taken 63 minutes
in a rotation time = 6 minutes
so now total rotation = 63/6
= 10.5
in a rotation distance which is equal to the 2πr
r = 210 m
2πr = 2× 22/7 × 210
= 1320 m
total distance = 1320×10.5
= 13860 m
displacement = distance between initial and final point which is equal to the diameter because last rotation is half
so displacement = 2×210
= 420m
speed = 13860/63
= 220 m/ min
velocity = 420/63
= 6.66 m/ min
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