Question

if an object is just dropped from top of a tower of height h find the expresssion for time taken by an object to reach the ground speed of the object at the time of striking the ground​

Answer 1

Answer:

Time taken, $t = \sqrt{\frac{2h}{g} }$

Final velocity, $v = \sqrt{2gh}$

Step-by-step explanation:

It's a free fall - Initial velocity is zero.

$h = \frac{1}{2} g t^2$  g is gravitational constant and t is time taken

∴ $t^2 = \frac{2h}{g}$

∴ $t = \sqrt{\frac{2h}{g} }$

Let's assume that the Ground speed of the object at the time of striking the ground was v.

∴ $v^2 = 2gh$

∴ $v = \sqrt{2gh}$

Answer 2

Answer:

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Step-by-step explanation: