Question

if an object is placed at a 10cm before a concave mirror of radius of curvature of 10 cm find the magnification​

Answer 1

Answer:

magnification is -1

Explanation:

I hope you got it

Answer 2

$\huge\tt\purple{♬•Answer:}$

Given that:

$focal\:length(f) =\frac{r}{2}$

$focal\:length(f) =\frac{-10}{2}=-5$

(focal length is negative for concave mirror)

$u= -10cm$

Now,

Mirror formula

$\frac{1}{f}=\frac{1}{v}+\frac{1}{u} \\ \\</p><p> →\frac{1}{-5}=\frac{1}{v}+\frac{1}{-10}\\ \\</p><p> →\frac{1}{v}=\frac{1}{-5}+\frac{1}{10}\\ \\</p><p> →\frac{1}{v}=\frac{1}{10}-\frac{1}{5}\\ \\</p><p>→\frac{1}{v}=\frac{1-2}{10}\\ \\</p><p>→\frac{1}{v}=\frac{-1}{10}\\ \\</p><p>→v= -10</p><p>$

Now,

$</p><p>→m=\frac{-v}{u}\\ \\</p><p></p><p>→m=\frac{-(-10)}{-10}\\ \\</p><p></p><p>→m=-1</p><p>$

Hence,magnification is - 1