If an object is thrown upwards and rises to a height of 10m.calculate the velocity with which the object was thrown upward and time taken by the object to reach the highest point
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Let velocity of object is u we know, at 10m height object will be rest .
so, final velocity = 0 A/C to kinematics equations,
v² = u² + 2aS 0 = u² +2(-g) × 10 0
= u² - 2 × 100 u² = 200u
= 10√2 m/s Time taken by the object to reach the highest point is t v = u + at 0
= 10√2 - 10t t = 10√2/10 sec t = √2 sec
Hope this helps you.
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