Question

If an object moves on a path which is like a right-angled triangle named ABC with sides 3cm,4cm and 5cm.Find the distance and displacement of the object if it travels along the longest side and reaches the opposite vertex.Explain!!!

Answer 1

Answer:

The longest side is 5 cm

If it travels along it to the opposite vertex

Distance = 4cm + 5cm

= 9cm

Displacement = shortest distance = 3 cm

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Answer 2

Answer:

$\underline{\huge{\red{ANSWER}}}$

Distance=3+4=7cm(longer distance)

Displacement=5cm(shortest possible distance)