Question

If an object of 10 cm height is placed at a distance of 36 cm from a concave mirror of focal length 12 cm , find the position , nature and height of image.

Answer 1

since , 1/v = 1/f - 1/u
                 =1/(-12) - 1/(-36)
                  = -2/36        = -1/18
 therefore , v = -18
now magnification M = image height / object height = -v/u
                                 i.e, image height = 10 x -(-18)/-36
                                                          = 10 x (-1/2)
                                                           = -5
Therefore, image would be real and inverted

Answer 2

since , 1/v = 1/f - 1/u

                 =1/(-12) - 1/(-36)

                  = -2/36        = -1/18

 therefore , v = -18

now magnification M = image height / object height = -v/u

                                 i.e, image height = 10 x -(-18)/-36

                                                          = 10 x (-1/2)

                                                           = -5

Therefore, image would be real and inverted

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