Question

if an object of mass 24kg is moving with an acceleration of 3m/s . Calculate the force applied​

Answer 1

Answer:

F=ma

here m=24kg and a=3m/s^2

therefore Force = 24×3 = 72N

Answer 2

Provided that:

• Mass = 24 kg
• Acceleration = 3 mps sq.

To calculate:

• The force applied

Solution:

• The force applied = 72 Newton

Using concept:

• Second law of motion that tell us about the formula to calculate the force.

Using formula:

• Force = Mass × Acceleration

Required solution:

»»» Force = Mass × Acceleration

»»» F = m × a

»»» F = ma

»»» F = 24 × 3

»»» F = 72 N

»»» Force = 72 Newton

Additional information:

Something about acceleration:

$\begin{gathered}\boxed{\begin{array}{c}\\ \bf What \: is \: acceleration? \\ \\ \sf The \: rate \: of \: change \: of \: velocity \: of \: an \\ \sf object \: with \: respect \: to \: time \\ \sf is \: known \: as \: acceleration. \\ \\ \sf \star \: Negative \: acceleration \: is \: known \: as \: deceleration. \\ \sf \star \: Deceleration \: is \: known \: as \: retardation. \\ \sf \star \: It's \: SI \: unit \: is \: ms^{-2} \: or \: m/s^2 \\ \sf \star \: It \: may \: be \: \pm ve \: or \: 0 \: too \\ \sf \star \: It \: is \: a \: vector \: quantity \\ \\ \bf Conditions \: of \pm ve \: or \: 0 \: acceleration \\ \\ \sf \odot \: Positive \: acceleration: \: \sf When \: \bf{u} \: \sf is \: lower \: than \: \bf{v} \\ \sf \odot \: Negative \: acceleration: \: \sf When \: \bf{v} \: \sf is \: lower \: than \: \bf{u} \\ \sf \odot \: Zero \: acceleration: \: \sf When \: \bf{v} \: \sf and \: \bf{u} \: \sf are \: equal \end{array}}\end{gathered}$