Question

If an object project vertically upword with speed half of the escape speed of earth then the max height attained by it is

Answer 1

Escape speed of earth = 11.2km/s = 11200m/s

Initial velocity = u = 11200/2 = 5600m/s

final velocity = v = 0m/s

acceleration due to gravity = g = -10m/s²

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V² - u² = 2as

S = v²-u²/2a

S = (0)²-(5600)²/2(-10)

S = -3136×10⁴/-20

S = 156.8×10⁴m

S = 1.568×10^6 m .
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