Question

If an object starts from rest, it covers a distance of 50 m in 10 sec. calculate

a. Final velocity of the object

b. Acceleration​

Answer 1

Answer:

here,u=0

d=50 m

and t=10 s

then using , s= ut +at^2/2

50=0+a(10)^2/2

50=a*100/2

50=50a

a=1 m/s2

now using v=u+ at

v=0+1*10

v=10m/s

Answer 2

Answer:

Acceleration = 1 m/s²

Final velocity = 10 m/s

Step-by-step explanation:

Given:

• Initial velocity = 0 m/s
• Distance covered = 50 m
• Time taken = 10 s

To Find:

• Final velocity of the object
• Acceleration

Solution:

First we have to find the acceleration of the object.

By the second equation of motion we know that,

s = ut + 1/2 × a × t²

where s = distance covered

           u = initial velocity

           a = acceleration

           t = time

Substitute the data,

50 = 0 +  1/2 × a × 10²

50 = 50 a

a = 50/50

a = 1 m/s²

Hence acceleration of the object is 1 m/s².

Now we have to find the final velocity of the object.

By the third equation of motion we knows that,

v² - u² = 2as

where v = final velocity

           u = initial velocity

           a = acceleration

           s = distance covered

Substitute the data,

v² - 0² = 2 × 1 × 50

v² = 100

v = √100

v = 10 m/s

Hence final velocity of the object is 10 m/s.

Notes:

The three equations of motion are:

• v = u + at
• s = ut + 1/2 × a × t²
• v² - u² = 2as