Question

If an object starts from rest with an acceleration of 2m/s2
, calculate the
distance covered by an object in 60 sec.

Answer 1

Answer:

3600 metre

Explanation:

s = ut +1/2× at'2

0×60 + 60×60

3600

Answer 2

$\boxed{\rm{\large{\red{Question\longrightarrow }}}}$

If an object starts from rest with an acceleration of 2m/s², calculate the distance covered by an object in 60 sec.

$\boxed{\rm{\large{\orange{Given\longrightarrow }}}}$

• Acceleration [a] = 2m/s²
• Time interval [t] = 60 sec
• Initial speed [u] = 0m/s (starts from rest)

$\boxed{\rm{\small{\blue{Find\longrightarrow }}}}$

Distance covered-?

$\boxed{\rm{\large{\purple{Formula \ used\longrightarrow }}}}$

$\boxed{\tt{ s= ut + \dfrac{1}{2} at ^2 }}$

• s= distance covered

• u= initial speed

• t= time

• a= acceleration

$\boxed{\rm{\large{\green{SoLution\longrightarrow }}}}$

By using Second equation of motion,

$\boxed{\bf{ \bigstar s= ut + \dfrac{1}{2} at ^2 \bigstar }}$

Put value of u, t and a in the formula we get,

$\sf{ s= 0 \times 60 + \dfrac{ 1}{2} \times 2 \times 60^2 }$

$\sf{ s= 0+ 60\times 60}$

$\sf{ s= 3600}$

$\underline{\bf{\pink{ \star \therefore Distance\ covered\ by \ object \ is\ 3600 m\star}}}$

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