Physics, asked by rajanalae, 8 months ago

if an object travels with a velocity v1 for the half distance V2 remaining half then average velocity​

Answers

Answered by VedswaroopK
1

Answer:

Time taken to travel x distance with speed v1 is, t¹ = x/v1.

Time taken to travel next x distance with speed v2 is , t² = x/v2.

Total time t= t¹ +t² =x{( v1+v2)/v1.v2}.

Average velocity= [(x+x)/t]

=2x/x{(v1+v2)/v1.v2}

=2.v1.v2/(v1+v2).

Answered by mallepallisreeram
2

Answer:

2V1V2/V1+V2

Explanation:

average velocity = total displacement / total time

v = s/t

t = s/v

t1 = s/2/v1 (or) s/2V1

t2 = s/2/v2 (or) s/2V2

average velocity = S/2+S/2/ S/2V1+S/2V2

WE WILL TAKE COMMON S/2

S/2(1+1)/S/2(1/V1+1/V2)

S/2 GETS CANCELLED

2/1/V1+1/V2

TAKE L.C.M V1,V2

2/V1+V2/V1V2

=> 2V1V2/V1+V2

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