If an oject covers distance 0km at 8am ,286km at 2pm and 786km at 10pm.which type of motion would it be between 8am and 10pm
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velocity at 8 am =0
velocity at 2pm= 286/6=47.6 app.
velocity at 10 pm= 500/8=62.5
hence the velocity is increasing
so the motion of the object is non uniform motion with non uniform acceleration
velocity at 2pm= 286/6=47.6 app.
velocity at 10 pm= 500/8=62.5
hence the velocity is increasing
so the motion of the object is non uniform motion with non uniform acceleration
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