If α and 1/α are zeros of a polynomial 4x2-2x+(k-4) find the value of k?
Answers
Answered by
1236
Hi ,
Compare 4x² - 2x + ( k - 4 ) with
ax² + bx + c ,
a = 4 ,
b = - 2 ,
c = k - 4 ,
Product of the zeroes = c/a
Alpha × 1/alpha = ( k - 4 ) / 4
1 = ( k - 4 ) / 4
4 = k - 4
4 + 4 = k
8 = k
Therefore ,
k = 8
I hope this helps you .
: )
Compare 4x² - 2x + ( k - 4 ) with
ax² + bx + c ,
a = 4 ,
b = - 2 ,
c = k - 4 ,
Product of the zeroes = c/a
Alpha × 1/alpha = ( k - 4 ) / 4
1 = ( k - 4 ) / 4
4 = k - 4
4 + 4 = k
8 = k
Therefore ,
k = 8
I hope this helps you .
: )
Answered by
212
see attachment to this question because it is Section a number one question
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