If θ and 3 θ-30◦ are acute angles such that sin θ=cos(3 θ-30◦), then find the value of tan θ
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I hope this helps
suppose that 'A' is the angle in given question.
sinA=cos (3A-30)
A is acute angle so,
sin(90-A)=cos(3A-30) {sin (90-A)=cosA}
cosA=cos (3A-30)
comparing both side
A=3A-30
3A-A=30
2A=30
A= 30/2
A=15
suppose that 'A' is the angle in given question.
sinA=cos (3A-30)
A is acute angle so,
sin(90-A)=cos(3A-30) {sin (90-A)=cosA}
cosA=cos (3A-30)
comparing both side
A=3A-30
3A-A=30
2A=30
A= 30/2
A=15
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