If
and
ar COSA SinB, Y = r COSA
COSB
Z= r sin A, then prove that xsquare + y² + zsquare = rsquare
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Step-by-step explanation:
LHS = (r cosA cosB)2 + (r cosA sinB)2 + = (r sinA)?
= r2 cos?A cos?B + r 2 cos?A sinB + r2 sin2A
= r2 cos?A (cos?B + sin?B) + r2 sin²A
= r 2 (cos?A + sin?A) = r2 = RHS !!
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