If α and β are roots of the equation
X^2-px+16 satisfy relation α^2+β^2=9 write value of p
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Heya !!
P ( X ) = X² - PX + 16
Here,
A = Coefficient of X² = 1
B = Coefficient of X = -P
And,
C = Constant term = 16
Sum of zeroes = -B/A
Alpha + Beta = -(-P) /1
Alpha + Beta = P ---------(1)
And,
Product of zeroes = C/A
Alpha × Beta = 16 --------(2)
Given that : (Alpha)² + (Beta)² = 9
=> ( Alpha - Beta )² + 2Alpha Beta = 9
=> (P)² + 2 × 16 = 9
=> P² = 9 - 32
=> P² = -23
=> P = ✓-23
P ( X ) = X² - PX + 16
Here,
A = Coefficient of X² = 1
B = Coefficient of X = -P
And,
C = Constant term = 16
Sum of zeroes = -B/A
Alpha + Beta = -(-P) /1
Alpha + Beta = P ---------(1)
And,
Product of zeroes = C/A
Alpha × Beta = 16 --------(2)
Given that : (Alpha)² + (Beta)² = 9
=> ( Alpha - Beta )² + 2Alpha Beta = 9
=> (P)² + 2 × 16 = 9
=> P² = 9 - 32
=> P² = -23
=> P = ✓-23
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