if α and ß are the roots of the equation x2 +5x + 6 = 0 . Find the value of 1/ α2 + 1/ß2
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Answer:
Let α+3=x
∴α=x−3 (Replace x by x-3)
So the required equation is
⇒(x−3)
2
−5(x−3)+6=0
⇒x
2
−6x+9−5x+15+6=0 ......... (1)
⇒x
2
−11x+30=0
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