Math, asked by rabiherodown, 6 months ago

If α and β are the roots of the equation3x² +8x +2= 0 then (1/α +1/β) ​

Answers

Answered by Anonymous
0

Answer:

-8/2

Step-by-step explanation:

Equation is 3x² + 8x + 2

On comparing this equation ,

a = 3 , b = 8 , c = 2

Now,

(1)

We know,

Sum of zeroes = -b /a

=> α + β = -8/3

Also,

(2)

product of zeroes = c/a

αβ = 2/3

Given,

(1/α) + (1/β)

=> (α + β)/αβ

=> (-8/3) * (3/2)

=> -8/2

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Answered by snowwhiteaug18
1

Answer:

-4

Step-by-step explanation:

3x² +8x +2= 0

Using the standard form of a quadratic equation,

a = 3, b = 8, c = 2

sum of the roots,

α + β = - b/a

         = - (8)/3

product of the roots,

αβ = c/a

     = 2/3

Let 1/α be R₁ and 1/β be R₂

sum of the roots,

R₁ + R₂ = 1/α + 1/β

           = (β + α)/αβ

substituting our answers from above,

            = (-8/3) divided by 2/3

            = -8/3   x 3/2   (reciprocal)

            = - 4

Thus, (1/α +1/β) ​is -4.

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