If α and β are the roots of the polynomial x2 -4x+5 then α+β is
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Solution:
Since, α and β are roots of the quadratic equation
x2−4x+5=0
So, α+β=4 and αβ=5 ... (i)
Now, (α2+β)+(α+β2)=(α2+β2)+(α+β)
=(α+β)2−2αβ+(α+β)
=16−10+4=10
and (α2+β)(α+β2)=α3+α2β2+βα+β3
=α3+β3+αβ(αβ+1)
=(α+β)(α2+β2−αβ)+αβ(αβ+1)
=(α+β)[(α+β)2−3αβ]+αβ(αβ+1)
=4[16−15]+5(5+1)
=4+30=34
So, the quadratic equation whose roots are
(α2+β) and (α+β2) is
x2−(α2+β+α+β2)x+(α2+β)(α+β2)=0
⇒x2−10x+34=0
Step-by-step explanation:
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