If α and β are the zeroes of the polynomial then find 1/α+ 1/β , if polynomial is X2 +6x +2
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Answer:
1/α + 1/β = -3
Step-by-step explanation:
Given that,
- Quadratic equation, x² + 6x + 2 = 0
On comparing with ax² + bx + c = 0 ; we get,
↪ a = 1 , b = 6 , c = 2
Given that,
- α and β are the zeroes of the polynomial.
↪ Sum of roots = -b/a
↪ α + β = -6/1
↪ α + β = -6
↪ Product of roots = c/a
↪ αβ = 2/1
↪ αβ = 2
Hence,
↪1/α + 1/β = α+β/αβ
↪ 1/α + 1/β = -6/2
↪ 1/α + 1/β = -3.
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