If α and ß are the zeroes of the polynomial x²-5x+6. Then the values of α⁴ ß²+ α²ß ⁴ is
Answers
Step-by-step explanation:
It is given that à and ß are the zeroes of polynomial x²- 5x+6
Let Polynomial be f(x) = x²- 5x+6
{ On comparing; a = 1 , b = -5 and c = 6 }
Here, Relationship Between Zeros:
☞ Sum of Zeroes = -b/a
= -(-5)/1
= 5
☞ Product of Zeros = c/a
= 6/1
= 6
Now, We have to Find the Value of 1/à + 1/b - 2àß
☛ 1/à + 1/b - 2àß
= à+ß/àß - 2àß
= 5/6 - 2*6
= 5/6 - 12
= 5-72
= - 67
Therefore, Value of 1/à + 1/b - 2àß is -67.
Solution:
It is given that à and ß are the zeroes of polynomial x²- 5x+6
Let Polynomial be f(x) = x²- 5x+6
{ On comparing; a = 1 , b = -5 and c = 6 }
Here, Relationship Between Zeros:
☞ Sum of Zeroes = -b/a
= -(-5)/1
= 5
☞ Product of Zeros = c/a
= 6/1
= 6
Now, We have to Find the Value of 1/à + 1/b - 2àß
☛ 1/à + 1/b - 2àß
= à+ß/àß - 2àß
= 5/6 - 2*6
= 5/6 - 12
= 5-72
= - 67
Therefore, Value of 1/à + 1/b - 2àß is -67.