If α and β are the zeroes of the quadratic polynomial f(x)=x^{2} -4x+6 , then find the value of α⁴β³+α³β⁴.
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Step-by-step explanation:
GIVEN:
α and β are the zeroes of the quadratic polynomial f(x)=x^{2} -4x+6.
Sum of zero = α + β = - b/a = 4/1 = 4. ....... 1
Product of zero = αβ = c/a = 6 ......... 2
So,
α⁴β³+α³β⁴ = α³β³(α+β)
= (αβ)³(α+β) (put the value
from eq. 1 and 2)
= ( 6)³(4)
= 216×4
= 864
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