if α and β are the zeroes of the quadratic polynomial p(x)=ax2+bx+c then evaluate 1/α^4 + 1/β^4
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Answer:
p(x)=ax2+bx+c
α+β=-b/a
αβ=c/a
1/α+1/β-2αβ=(β+α)/αβ -2αβ
=(-b/a)/(c/a) -2c/a
=-b/c -2c/a
=-(ab+2c^2)/ca
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