Math, asked by shriyansnayakhd12, 10 months ago

if α and β are the zeroes of the quadratic polynomial p(x)=ax2+bx+c then evaluate 1/α^4 + 1/β^4

Answers

Answered by afreen12qwth
1

Answer:

p(x)=ax2+bx+c

α+β=-b/a

αβ=c/a

1/α+1/β-2αβ=(β+α)/αβ -2αβ

=(-b/a)/(c/a) -2c/a

=-b/c -2c/a

=-(ab+2c^2)/ca

HOPE IT HELPS YOU

HAVE A GOOD DAY AHEAD :)

Similar questions