Question

If α and β are the zeroes of the quadratic polynomial p(x) = x2 – 2x – 8, then find a
quadratic polynomial whose zeroes are 2α/β and 2β/α

Answer 1

Answer:

x^2 + 5x + 4

Step-by-step explanation:

Please mark it brainliest if it deserve

Answer 2

Answer:

x²+5x+4

Step-by-step explanation:

alfa+beta = -(-2)/1 = 2..........(1)

alfa.beta = -8/1 = -8..............(2)

solving these

=> alfa = 4 and beta = -2

therefore polynomial

= x²-( 2×4/-2 + 2×-2/4)x +(2×4/-2 × 2×-2/4)

= x²- ( -4-1)x + 4

= x²+5x+4

hope this helps you