If α and β are the zeros of a quadratic polynomial f(x) =x² - 3 x - 2 , find a quadratic polynomial whose zeros are β/α and α/β .
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Heya !!!
P(X) = X² - 3X - 2
Here,
A = 1 , B = -3 and C = -2
Sum of zeroes = -B/A
Alpha + Beta = -(-3)/1
Alpha + Beta = 3 ----------(1)
And,
Product of zeroes = C /A
Alpha × Beta = -2 ---------(2)
Sum of the zeroes quadratic polynomial whose zereos are Beta/Alpha and Alpha / Beta
Sum of zeroes = ( Beta / Alpha + Alpha / Beta)
=> ( Alpha + Beta ) / ( Alpha × Beta)
=> -3/2
And,
Product of zeroes = ( Beta / Alpha × Alpha / Beta )
=> ( Beta × Alpha ) /. ( Alpha × Beta )
=> -2/-2 = 1
Therefore,
Required quadratic polynomial = X²-(Sum of zeroes )X + Product of zeroes
=> X² - (-3/2)X + 1
=> X² + 3X/2 +1
=> 2X² + 3X + 2
★ HOPE IT WILL HELP YOU ★
P(X) = X² - 3X - 2
Here,
A = 1 , B = -3 and C = -2
Sum of zeroes = -B/A
Alpha + Beta = -(-3)/1
Alpha + Beta = 3 ----------(1)
And,
Product of zeroes = C /A
Alpha × Beta = -2 ---------(2)
Sum of the zeroes quadratic polynomial whose zereos are Beta/Alpha and Alpha / Beta
Sum of zeroes = ( Beta / Alpha + Alpha / Beta)
=> ( Alpha + Beta ) / ( Alpha × Beta)
=> -3/2
And,
Product of zeroes = ( Beta / Alpha × Alpha / Beta )
=> ( Beta × Alpha ) /. ( Alpha × Beta )
=> -2/-2 = 1
Therefore,
Required quadratic polynomial = X²-(Sum of zeroes )X + Product of zeroes
=> X² - (-3/2)X + 1
=> X² + 3X/2 +1
=> 2X² + 3X + 2
★ HOPE IT WILL HELP YOU ★
Anonymous:
Thank you
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