If α and β are the zeros of the polynomial 2x2 + 7x + 5, write the
value of α+β+2αβ.
answer with steps ..no Waste answers
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Answer:
no waste answer....
and required answer is 3/2
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Step-by-step explanation:
We have the equation
2x²+7x+5
Comparing it with ax²+bx+c we get , a=2 , b=7 and c =5
Thus , Sum of zeros (α+β) = -b/a = -7/2
And product of zeros (αβ)=c/a = 5/2
Now we have
⇒α+β+2αβ
⇒-7/2 +10/2
⇒3/2
Verification
We have the equation
2x²+7x +5
2x²+2x+5x+5
2x(x+1)+5(x+1)
(x+1)(2x+5)=0
x=-1 or x=-5/2
Thus now putting values in equation
α+β+2αβ
= -1+(-1/5)+2(-1)(-1/5)
=-7/5 +10/2
=3/2
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- Important Term
When a equation is in the form of ax²+bx +c then , the sum of zeros will be (-b/a) and its product of zeros will be (c/a) and this is also called relation of coefficient of zeros of polynomial
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