Question

If α and β are the zeros of x²– (5 + 7k)x + 35k, such that α² + β² = 172 is then the value of k is​

Answer 1

Explanation:

p(x)=x

2

−8x+k

a=1,b=−8,c=k

α+β=

a

−b

=8, αβ=

a

c

=k, α

2

+β

2

=40

α

2

+β

2

=(α+β)

2

−2αβ

40=8

2

−2k

2k=24

k=12