Math, asked by sanmugammaheshwari12, 10 months ago

If α and β are the zeros of x²-7X+12 then the value of 1/α + 1/β is

Answers

Answered by devildixit77
0

Answer:

x {}^{2} - 7x + 12 \\  \alpha  +  \beta  = 7 \di \\  \alpha  \beta  = 12 \\  \\  \\ 1 \div  \alpha  + 1  \div \beta   \\  \alpha  +  \beta  \div  \alpha  \beta     = 7  \div 12 = 0.58333...... \\

Answered by kanchan241dahima
1

Answer:

here your ans......

Step-by-step explanation:

Α and β  are  zeroes of  polynomial  x² - 7 x + 12

     αβ =  12      the product of the roots  is the  constant term

   α + β = 7      the sum of the roots is the  coefficient of x term , negated.

1/α + 1/β + 2 αβ

     =  (α + β) / αβ  +  2 αβ

     =  12 / 7 + 2 *  12  =  24 + 12/7  =  180/7

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