If * and ~ are two operations such that x*y = x ( multiplied by) x + 2 and x~y = x + y - 1. Find ((3 * 3 )*3)~3.
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((3*3)*3)~3=((3×3+2)*3)~3
=(8×8+2)~3
=66+3-1
=68
=(8×8+2)~3
=66+3-1
=68
adityarajkuntal:
Thanks fluffy and amru
Answered by
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Given :
→ * and ~ are two operations.
→ x*y = x (multiplied by) x+2 and x~y = x+y-1
Need to find out :
→ {(3*3)*3}~3
Solution :
⇒{(3*3)*3}~3 = {(3*3+2)*3}~3
⇒ (8*8+2)~3
⇒ (64+2)~3
⇒ 66+3-1
⇒ 68
Conclusion :
∴ {(3*3)*3}~3 = "68"
→ * and ~ are two operations.
→ x*y = x (multiplied by) x+2 and x~y = x+y-1
Need to find out :
→ {(3*3)*3}~3
Solution :
⇒{(3*3)*3}~3 = {(3*3+2)*3}~3
⇒ (8*8+2)~3
⇒ (64+2)~3
⇒ 66+3-1
⇒ 68
Conclusion :
∴ {(3*3)*3}~3 = "68"
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