If α and β are zeroes of the quadratic polynomial p(x)=x2-(k-6)x+(2k+1) and α+β= αβ, then find the value of k
Answers
Answered by
5
Hiii friend,
P(X) = X²-(K-6)+X+(2K+1).
A = 1 , B = (K-6) and C = 2K+1
Alpha + Beta = -B/A = -(K-6)/1
And,
Alpha × Beta = C/A =2K+1/1
According to question,
Alpha + Beta = Alpha × Beta
(K-6) = 2K+1
K-6 = 2K+1
2K-K =-6-1
K = -7
Hence,
K = -7
HOPE IT WILL HELP YOU.... :-)
P(X) = X²-(K-6)+X+(2K+1).
A = 1 , B = (K-6) and C = 2K+1
Alpha + Beta = -B/A = -(K-6)/1
And,
Alpha × Beta = C/A =2K+1/1
According to question,
Alpha + Beta = Alpha × Beta
(K-6) = 2K+1
K-6 = 2K+1
2K-K =-6-1
K = -7
Hence,
K = -7
HOPE IT WILL HELP YOU.... :-)
Similar questions